Important Formula For Clocks Problems
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Read MoreDecimal Shortcut Methods
1% = 1/100 = 0.01 2% = 2/100 = 0.02 = 1/50 3% = 3/100 = 0.03 4% = 4/100 = 0.04 = 1/25 (208)
Read MoreCube Shortcut Methods
Cubes of 101 to 115 : This one will help you when the TIME is given for 3 years i.e., (A) = (1+r/100)3 Remember in cubes of 101 to 115 the answer will be always in seven digits numbers.) Steps…
Read MorePercentage Shortcut Methods
Percent is derived from a phrase in latin “per centum” which means per hundred. It is a ratio with base (denominator) 100. It evolved as a concept so that there can be a uniform platform for comparing different values. To…
Read MoreLCM Shortcut Methods For Bank Exams
Find the LCM of 12, 18? Step 1: pick the highest of the given numbers of whom we have to find the LCM. In the above example question, pick 18 as it is highest among 12 and 18. (216)
Read MoreMathematical Shortcuts For All Exams
To check addition is correct : Add up the single digits of each individual number in the sum, until you are left with a single digit. -Add these single digits together until you are, once again, left with a single digit.…
Read MoreShortcut Tricks For Multiplication
Multiply any large number by 12 mentally in seconds To multiply any number by 12 just double last digit and thereafter double each digit and add it to its neighbour For example 21314 * 12 = 255768 Lets break it…
Read MoreAbbreviations for IBPS PO Main Exam: Computer Knowledge
ALGOL –Algorithm language ALU – Arithmetic Logic Unit AMD – Advanced Micro Devices ANSI- American National Standards Institute APCI- Application Layer Protocol Control Information ASCII – American Standard Code for Information Interchange (214)
Read MoreTop 10 Bank Exam Preparation Sites
1. Bank Exams India.com 2. Bank Po.org 3. Bestguru.com 4. Ibps Preparation.com 5. Exam2Win.com 6. Examsfunda.in 7. Bankexampreparation.com 8. Testfunda.com 9. Bankpreparation.in 10. Bankingawareness.com (246)
Read MoreTricks to Solve Quantitative Aptitude Questions On Numbers
Formulas of Number Series 1 + 2 + 3 + 4 + 5 + … + n = n(n + 1)/2 (12 + 22 + 32 + ….. + n2) = n ( n + 1 ) (2n + 1)…
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